At a room temperature, the surface tension of water is 72.0 mj.m^-2. what is the energy required to change a spherical drop of water with a diameter of 1.40 mm to smaller spherical of equal size?

the surface area of sphere of radius r is 4pi r^2 and the volume is 4pi r*3/3.

The answer is 1.15*10^-4

can you tell me how we get this answer

Subject | Science |

Due By (Pacific Time) | 11/15/2013 09:37 am |

Tutor | Rating |
---|---|

pallavi Chat Now! |
out of 1971 reviews More.. |

amosmm Chat Now! |
out of 766 reviews More.. |

PhyzKyd Chat Now! |
out of 1164 reviews More.. |

rajdeep77 Chat Now! |
out of 721 reviews More.. |

sctys Chat Now! |
out of 1600 reviews More.. |

sharadgreen Chat Now! |
out of 770 reviews More.. |

topnotcher Chat Now! |
out of 766 reviews More.. |

XXXIAO Chat Now! |
out of 680 reviews More.. |